$\text{Phthalic anhydride}$ $\xrightarrow {PCl_5} A$ $\xrightarrow {LiAlH_4} B$ $\xrightarrow {PCC} C$ $\xrightarrow [\Delta ] {OH^{-}} D$
Compound $D$ is :-

$3 CH_3COCH_3 \xrightarrow{HCl} (CH_3)_2C = CH - CO - CH = C(CH_3)_2$
This product $B$ is obtained when acetone is saturated with hydrogen chloride gas. $B$ can be:

Product $(C)$ of the above reaction is

In which of the following reactions is a new carbon-carbon bond not formed?

$A$ tertiary alcohol $H$ upon acid-catalysed dehydration gives a product $I$. Ozonolysis of $I$ leads to compounds $J$ and $K$. Compound $J$ upon reaction with $KOH$ gives benzyl alcohol and a compound $L$,whereas $K$ on reaction with $KOH$ gives only $M$.
$1.$ Compound $H$ is formed by the reaction of
$2.$ The structure of compound $I$ is
$3.$ The structures of compounds $J, K$ and $L$,respectively,are
$(A)$ $PhCOCH_3, PhCH_2 COCH_3$ and $PhCH_2 COO^{-} K^{+}$
$(B)$ $PhCHO, PhCH_2 CHO$ and $PhCOO^{-} K^{+}$
$(C)$ $PhCOCH_3, PhCH_2 CHO$ and $CH_3 COO^{-} K^{+}$
$(D)$ $PhCHO, PhCOCH_3$ and $PhCOO^{-} K^{+}$
Give the answer for questions $1, 2$ and $3.$

In the Cannizzaro reaction given below,the slowest step is $:-$
$2Ph-CHO \xrightarrow{\stackrel{\ominus}{O}H} PhCH_2OH + PhCO_2^{\ominus}$